Question

c program the function accepts two integers you are required to calculate the sum of numbers divisible by 3 and 5 between given two numbers and return the same.
ip:12,50 op:90​

Answer 1

Answer:

Program to print all the numbers divisible by 3 and 5 for a given number

Given the integer N, the task is to print all the numbers less than N, which are divisible by 3 and 5.Approach : For example, let’s take N = 20 as a limit, then the program should print all numbers less than 20 which are divisible by both 3 and 5. For this divide each number from 0 to N by both 3 and 5 and check their remainder. If remainder is 0 in both cases then simply print that number

Below is the implementaion

/ C++ program to print all the numbers

// divisible by 3 and 5 for a given number

#include <iostream>

using namespace std;

// Result function with N

void result(int N)

{

// iterate from 0 to N

for (int num = 0; num < N; num++)

{

// Short-circuit operator is used

if (num % 3 == 0 && num % 5 == 0)

cout << num << " ";

}

}

// Driver code

int main()

{

// input goes here

int N = 100;

// Calling function

result(N);

return 0;

}

// This code is contributed by Manish Shaw

// (manishshaw1)

Output :

0 15 30 45 60 75 90