Question

C program to find sum and average of four numbers using pointers

Answer 1

Explanation:

#include <stdio.h>

#include <conio.h>

int main()

{

int n,*p,sum=0,i;

float avg;

printf("How many numbers u want :: ");

scanf("%d",&n);

p=(int *) malloc(sizeof(int));

if(p==NULL)

{

printf("\nMemory Allocation unsuccessful.\n");

exit(0);

}

for(i=0;i<n;i++)

{

printf("\nEnter Number %d :: ",i+1);

scanf("%d",p+i);

}

for(i=0;i<n;i++)

{

sum=sum+*(p+i);

}

printf("\nThe Sum of %d Numbers is %d \n",n,sum);

avg=(float)sum/n;

printf("\nThe Average of %d Numbers is %0.2f \n",n,avg);

return 0;

}

Answer 2

#include <stdio.h>

#include <conio.h>

int n,*p,sum=0,i;

float avg;

printf("\nHOW MANY NUMBERS: ");

scanf("%d",&n);

p=(int *) malloc(n*2);

if(p==NULL)

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