Question

C++ program to read two integers as input and swap them using call by reference, without using a third variable.

Answer 1

Answer:

#include <iostream>  

using namespace std;  

int main()  

{  

int a=5, b=10;      

cout<<"Before swap a= "<<a<<" b= "<<b<<endl;      

a=a*b; //a=50 (5*10)    

b=a/b; //b=5 (50/10)    

a=a/b; //a=10 (50/5)    

cout<<"After swap a= "<<a<<" b= "<<b<<endl;      

return 0;  

}  

PLS MARK THE BRAILIEST PLS PLS PLS ......................

Answer 2

C++ program to read two integers as input and swap them using call by reference, without using a third variable.

#include <iostream>

using namespace std;

int main()

{

 int a = 5, b = 10;

 cout << "Before swapping." << endl;

 cout << "a = " << a << ", b = " << b << endl;

  a = a + b;

  b = a - b;

  a = a - b;

 cout << "\nAfter swapping." << endl;

 cout << "a = " << a << ", b = " << b << endl;

 return 0;

}

• In the above program two variables are assigned some value so that they can be swapped.
• After that some operations are used to swap the numbers and hence the output of the program will be the swapped numbers.