Question

c) prove that a diagnol of a rhombus bisects the angles at vertices
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Answer 1

Step-by-step explanation:

Let ABCD is a rhombus.

⇒ AB=BC=CD=DA [ Adjacent sides are eqaul in rhombus ]

In △AOD and △COD

⇒ OA=OC [ Diagonals of rhombus bisect each other ]

⇒ OD=OD [ Common side ]

⇒ AD=CD

∴ △AOD≅△COD [ By SSS congruence rule ]

⇒ ∠AOD=∠COD [ CPCT ]

⇒ ∠AOD+∠COD=180

o

[ Linear pair ]

⇒ 2∠AOD=180

o

.

∴ ∠AOD=90

o

.

Hence, the diagonals of a rhombus bisect each other at right angle.

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Answer 2

Step-by-step explanation:

Prove: If a quadrilateral is a rhombus, then the diagonals bisect the angles.

Given: Rhombus ABCD with diagonals BD and AC.

Prove: Segment AC bisects angles BAD and DCB. Segment DB bisects angles ADC and CBA.