Question

c. Prove that the kinetic energy of a
freely falling object on reaching
the ground is nothing but the
transformation of its initial potential
energy
​

Answer 1

Answer:

Explanation:

Total energy at initial position = K.E + P.E = 0 + mgh

Total energy when it reaches the ground = K.E + P.E = 0.5mv^2 + 0

Velocity when it reaches the ground = sqrt(2gh)

Substitute velocity in total energy equation

Total energy when it reaches the ground = 0.5mv^2 = 0.5m * 2gh = mgh

We found that total energy when it reaches the ground = Total energy at initial position.

In other words, kinetic energy with which it hits the ground is the transformation of its initial potential energy.

Answer 2

Answer:

Prove that the kinetic energy of afreely falling object on reaching the ground is nothing but the transformation of its initial potential energy

Let the velocity of the object be vC and the object has fallen through a distance h . ... Thus, it can be concluded that the kinetic energy of a freely falling object on reaching the ground is nothing but the transformation of its initial potential energy.

Explanation: