c. Prove that the kinetic energy of a
freely falling object on reaching
the ground is nothing but the
transformation of its initial potential
energy.
Answers
Explanation:
The energy of an due to its position the sum of an object kinetic and potential energy .
Potential energy is the energy which is stored in an object due to a specific state or position is called potential energy e.g. water stored in an dam.
Kinetic energy is energy obtained from motion is called kinetic energy .
hence , when the stored water is released from dam the energy gets transformed from potential to kinetic .
Thus in such a way , when a freely falling object reaches the ground it's energy gets transformed into its initial kinetic into potential energy ..
Answer:
Let the object beat a point A i.e. at height n above the surface of Earth as shown in the figure above
✷ At point A
The object is stationary i.e. its initially velocity U=O
kinetic energy , k=12 MV2=12mu²=12
MV=12 MU2=O potential energy, V=gh... ... ...
✷ B point
Lets the velocity of the object be VB and the object has fallen through distance x.
Using third equation of motion we have V²=B=O+2
gx= V²B² = O+2 gx = VB² = 29 x kinetic energy k = 12m V2B
= Mg x K =12mvB2= mg x potential energy U=mg [h-x] ...[ii]
✷ C point
Lets the velocity of the object be VC and the get for fallen through a distance h.
Using third equation of motion we have V² C=O+2
gh=V²B²=hv 2 ghv = C2 = O+2gh
B²=a²gh kinetic energy, k = 12 mVc = mghk=12
MVC2=mgh ... ... ...[iii]
Point C, Thus, it can be concluded that the kinetic energy of a freely falling object or reaching the ground is nothing bu the transformation of its initial potential energy.
