c. r equation in polar coordinate
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Let f(z) = u(x,y) +iv(x,y) be a function on an open domain with continuous partial derivatives in the underlying real variables. Then f is differentiable at z=x+iy if and only if
∂u
∂x
(x,y) =
∂v
∂y
(x,y) and
∂u
∂y
(x,y) = −
∂v
∂x
(x,y). So we have f′(z)=
∂u
∂x
(z)+i
∂v
∂x
(z). Let f(z) = f(reiθ)= u(r,θ) +iv(r,θ) be a function on an open domain that does not contain zero and with continuous partial derivatives in the underlying real variables. Then f is differentiable at z = reiθ if and only if r
∂u
∂r
=
∂v
∂θ
and
∂u
∂θ
= −r
∂v
∂r
.
Sorry, if this is not very good. I just decided to start learning complex analysis today...
this is your answer
∂u
∂x
(x,y) =
∂v
∂y
(x,y) and
∂u
∂y
(x,y) = −
∂v
∂x
(x,y). So we have f′(z)=
∂u
∂x
(z)+i
∂v
∂x
(z). Let f(z) = f(reiθ)= u(r,θ) +iv(r,θ) be a function on an open domain that does not contain zero and with continuous partial derivatives in the underlying real variables. Then f is differentiable at z = reiθ if and only if r
∂u
∂r
=
∂v
∂θ
and
∂u
∂θ
= −r
∂v
∂r
.
Sorry, if this is not very good. I just decided to start learning complex analysis today...
this is your answer
arun12695:
perfect
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