C(s)+ H2O (9) -> CO(g) + H2(g)
deltanG not at l000 K= -8.1kJ
what is equillibrium constant k
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Answer:
60 g of water gas correspond to
30
60
=2 moles of CO and 2 moles of H
2
90 g of steam corresponds to
18
90
=5 moles of H
2
The initial moles of CO,H
2
O,CO
2
and H
2
are 2,5,0 and 2 moles respectively.
The moles of CO,H
2
O,CO
2
and H
2
present at equilibrium are 2−x,5−x,x and 2+x moles respectively.
The expression for the equilibrium constant is K
c
=
[CO][H
2
O]
[CO
2
][H
2
]
Substitute values in the above expression.
3=
(
2
2−x
)(
2
5−x
)
(
2
x
)(
2
2+x
)
Thus x=1.5 and [H
2
]=2+1.5=3.5M
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