Chemistry, asked by Sekhon4432, 8 months ago

C(s)+ H2O (9) -> CO(g) + H2(g)
deltanG not at l000 K= -8.1kJ
what is equillibrium constant k​

Answers

Answered by sk16228531886
1

Answer:

60 g of water gas correspond to

30

60

=2 moles of CO and 2 moles of H

2

90 g of steam corresponds to

18

90

=5 moles of H

2

The initial moles of CO,H

2

O,CO

2

and H

2

are 2,5,0 and 2 moles respectively.

The moles of CO,H

2

O,CO

2

and H

2

present at equilibrium are 2−x,5−x,x and 2+x moles respectively.

The expression for the equilibrium constant is K

c

=

[CO][H

2

O]

[CO

2

][H

2

]

Substitute values in the above expression.

3=

(

2

2−x

)(

2

5−x

)

(

2

x

)(

2

2+x

)

Thus x=1.5 and [H

2

]=2+1.5=3.5M

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