Question

c) Solve by cross multiplication method
x-3y-7=0
3x – 3y = 15​

Answer 1

Answer:

but cross multiplication method is deleted

Answer 2

$\huge\mathbb\pink{Incorrect Question}$

x-3y-7=0

3x – 3y = 15

$\huge\mathbb\pink{Correct Question}$

X-3y-7=0

3x-3y-15=0

$\huge\mathbb\pink{Answer}$

x = 4 and y = 1

Step-by-step explanation:

Given : ${ \ x \ - 3 y \ 7 \ = \ 0}$

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎${ \ 3x - \ 3y \ - 15 \ = 0}$

To Find :  solve it by cross multiplication method

solve it by cross multiplication methodSolution:

Cross multiplication method

Equations :

Equations : ${a_1x+b_1x+c_1}=0$

$\frac{x}{b_1c_2-c_1b_2}=\frac{y}{a_1c_2-a_2c_1} =\frac{1}{a_1b_2-a_2b_1}$

Comparing the given equations

${ \ x- \ 3y \ - 7 \ = 0}$

${ \ 3x \ - 3y \ - 15 \ = 0}$

$\frac{x}{(-3)(-15)-(-7)(-3)}=\frac{y}{(1)(-15)-(3)(-7)} =\frac{1}{(1)(-3)-(3)(-3)}$

$\frac{x}{24}=\frac{y}{6} =\frac{1}{6}$

$\frac{x}{4}=\frac{y}{1} =\frac{1}{1}$

So, x = 4 and y = 1

$<font color=magenta>$ Hope it's helps you

Plz marked in brainlest answer