Question

c) Solve by the method of substitutions
3x + 2 = 3, 3y - 2x = 2​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

3x + 2 = 3

=> 3x = 3-2

=> $\boxed{x = {\frac{1}{3}}}$

Substitute x in 3y-2x =2

=> 3y-2 ( ${\frac{1}{3}}$ ) =2

=> 3y- ${\frac{2}{3}}$=2

=> 3y = 2+${\frac{2}{3}}$

=> 3y = ${\frac{6+2}{3}}$

=>${\boxed {y = {\frac{8}{9}}}}$