Question

(c)Solve graphically: 2x - y + 3 =0;x - 2y + 1 = 0​

Answer 1

Step-by-step explanation:

Given, 2x + y – 3 = 0…….

(i) 2x – 3y – 7 = 0…….

(ii) For equation

(i), ⇒ y = (3 – 2x)

When x = 0, we have

y = (3 – 2(0)) = 3 When x = 1, we have y = (3 – 2(1)) = 1

Thus we have the following table giving points on the line 2x + y – 3 = 0 x 0 1 y 3 1 For equation (ii),

We solve for y: ⇒ y = (2x–7)3(2x–7)3 So, when

x = 2 y = (2(2)–7)3(2(2)–7)3 = -1 And, when

x = 5 ⇒ y = (2(5)–7)3(2(5)–7)3 = 1

Thus we have the following table giving points on the line 2x – 3y – 7 = 0 x 2 5 y -1 1 Graph of the equations

(i) and (ii) is as below: Clearly the two lines intersect at a single point P (2, -1) Hence, x= 2 and y = -