c. Solve the following numerical :- 4*10=40 1. A man divides, Rs 90,000 among wife, son and daughter in the ratio- --- Find the amount received by them. 2. A train 80m long crosses a platform 120m in length in 20 seconds. Find the speed of the train in km/hr. 3 A man drives 180km from city A to city B in 4 hours 10 minutes and returns to the city A is 3 hours 20 minutes. Find the average speed of the whole journey. 4. If 24.8 m of a uniform iron rod weighs 82.15 kg, what will be the length of 26.5kg of the same rod? 5. Simplify 40 - 63 + 3 of 7 - (-23 + 5) = 6 * 2 11 (5 + 1) + [ 43-444-12 - 3. 1. ) 6. The total weight of certain bags of rice is 650.16 kg. If each bag weighs 10.32 kg, find the number of bags. 7. A car covers a distance of 189-km in 4 hours. Find the distance covered in one hour. 8. A cement company earns a profit of Rs. 8 per bag of white cement sold and a loss of Rs. 5 per bag of grey cement sold. What is the number of white cement bags it must sell to have neither profit nor less, if the number of grey cement bags sold is 6400? 9. The ratio of the income to the expenditure of a family is 8:5. Find the savings, if the income is R$ 48,000.
Answers
1.) Total=$90,000
Ratio given to wife, son and daughter= 1/3:1/4:1/6
Therefore wife gets= 1/3 of $90000=$30,000
Son = 1/4 of $90000=$22500
Daughter=1/6 of 90000=$15000
Remaining money is the man's money.
2.) Total distance= length of train + length of platform
80+120= 200 m (0.2 kmph)
Time = 20 second but need in hours so 20/(3600)= 1/(180)
Speed = distance / time = 0.2*180= 36 kmph
3.) We are given that the distance between city A and city B is 180km
The man moves to city B from city A and then comes back to city A.
Let us now calculate the total distance travelled by a man by taking twice the distance from city A to city B.
That is, 2×180=360km
Now, we are also given that the time taken by a man from city A to city B is 4 hours 10 minutes and time taken from city B to city A is 3 hours 20 minutes.
The total time taken is the sum of the time taken on both journeys.
Hence, the total time taken is 4 hours 10 minutes + 3 hours 20 minutes = 7 hours 30 minutes
Now, convert the total time taken in hours, therefore, divide the minutes by 60.
7 hours 30 minutes = 7 + 3060 hours ⇒ (7 + 0.5) hours ⇒ 7.5hours
As it is known that speed = distance time
Therefore, average speed can be calculated by dividing total distance covered by total time taken.
Thus, average speed is 3607.5=48km/hr
Hence, the average speed of the journey is 48km/hr.
4.) If 24.8m rises to 82.15 kg
Then x m rises to 26.5kg
Then x = (26.5x24.8)/82.15
x =657.2/82.15
x =8 m
5.) According to BODMAS
= 40-63÷21-(-23+5)÷6×2
= 40-63÷21-(-18)÷6×2
= 40-63÷21+18÷6×2
= 40-3+3×2
= 40-3+6
= 40+6-3
= 46-3
= 43
6.) Total weight = 650.16 kg
One bag = 10.32 kg
No. of bags = 650.16 ÷ 10.32 = 63 bags
7.) Car cover 568/3 km in 40/9 hrs
Car cover distance in 1 hours=568/3÷40/9
=213/5 km or 42 13/5 km
8.) 25,000 > 24,000
Thus, loss occurs.
The total loss of the cement company = Total loss by selling the given number of bags - Total profit earned by selling the given number of bags.
Substituting the corresponding values, we get
Total loss = 25,000 – 24,000 = 1000
Thus, the total loss of the cement company is equal to Rs.1000.
9.) Ratio is 8:5
Savings will be 3x.
Then 3x = 18000
Therefore saving will be of 18000.