Math, asked by hemdecor03gmailcom, 1 month ago


(c) Some identical cards are numbered from 2 to 25 and well shuffled.
When a card is drawn randomly, what is the probability that the card has:
(i) a prime number
(ii) a multiple of 2 and 3
(iii) not a multiple of 7.
(iv) a perfect cube number.​

Answers

Answered by Pratik2759
0

Answer:

(I) prime numbers between 2 and 25 are

2,3,5,7,11,13,17,19,23 i.e a total of 9 prime numbers

therefore the probability of getting a prime number = 9/24

(ii) a multiple of 2 and 3 is actualy a multiple of 6 therefore there are 6,12,18,24 i.e a total of 4 such numbers.

so probability=4/24=1/6

(iii)there are 3 multiples of 7 therefore there are are 21 which are not

so probability=21/24

(iv) there is only one perfect cube which is 8

so probability=1/24

Answered by tarunchaklader8215
0

Step-by-step explanation:

this is all my answer

please make me as a brainlist

Attachments:
Similar questions