C takes twice the number of days to do a piece of work than a takes. A and b together can do it in 6 days while b and c can do it in 10 days. In how many days a alone can do the work
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Answer:
15 days
Step-by-step explanation:
A+B in 6 days
B+C in 10 days
in sense of work
suppose each work in a day
A works A, B works B, C works C
A+B = 1/6
B+C =1/10
then
A+B+C = 1/6+1/10
A+B+A/2 = 7/60
( Work of A twice than C because C takes twice days than A )
2A+B+A = (7/60 )×2=7/30
3A+B = 7/30
now
equation 1 -------
A+B= 1/6
equation 2-------
3A+B = 7/30
if
equation 2 - equation 1
then,
2A = 7/30-1/6 = 7-5/30 = 2/30 =1/15
then A work in 15 days
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