Physics, asked by yoga2020lakshmi, 3 months ago

(c) The area of cross section of press plunger of a hydraulic press is 4m. It is
required to overcome a resistive load of 400kgf on it. Calculate the force
required on the pump plunger if the area of cross section of the pump plunger
is 0.01m2.(4)​

Answers

Answered by geetachaudhary2210
0

Answer:

The area of cross section of press plunger of a hydraulic press is 4m2 4m . It is required to overcome resistive load of 400kgf on it. Calculate the force required on the pump plunger if the area cross section of plunger is 0.01m2. manishvermadwl123 is waiting for your help.

Explanation:

may it help you

Answered by priyadpriyadarshini3
0

Answer:

Load=900kgf,Effort(E)=?

Area of cross section of the press plunger =a

1

=9m

2

Area of cross - section of the pump plunger =a

2

=0.03m

2

By Pascal's law,

Pressure exerted by pump plunger = pressure exerted on press plunger.

i.e.,

E

L

=

a

2

a

1

E

900kgf

=

0.03m

2

9m

2

⇒E=

9m

2

900kgf×0.03m

2

=3kgf.

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