Math, asked by gobi81836, 7 months ago

(c) The digit at the ones place of
 {67}^{2}
is ________.

Answers

Answered by mendababurao123
0

Step-by-step explanation:

the answer is 9.

because 7 square = 49 . last digit is 9

Answered by GangsterTeddy
2

Step-by-step explanation:

9 will be the ones place digit

67×67 = here we have to first multiply 7×7 so we will get 49

so 67×67=4489

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