Question

c) The driver of a train travelling at 40ms applies the brakes as a train enters the station. The train slows down at a rate of 2ms?. Calculate the distance travelled?​

Answer 1

Answer:

Initial speed =u=40ms

−1

Acceleration =a=−2ms

−2

(Retardation, hence negative)

Final speed =v=0

Now, s= Distance train travels before stopping

Now, we know from the equations of motion that

v

2

=u

2

+2as

0=40

2

+2×(−2)×s

4s=1600⇒s=400m

So, the train covers 400m before stopping

Also, the length of platform =400m

So, the train stops in time

Answer 2

Answer:

38ms

Explanation:

because the train driver drives in 40ms

then the

train slows at the station at the rate of 2ms

the we subtract