Question

c) The edge length of a crystal which crystallises in FCC is 1.602pm. Calculate its radius.​

Answer 1

15-(7)9+7)7(9()+8686-7&-78582=789(67)

Answer 2

Given: Edge length of crystal in FCC is 1.602 pm

To Find: Radius.

Explanation:

In FCC(Face centered cell) lattice:

$\sqrt{2} a=4r$

Where a is the edge length

r is the radius

so, $\sqrt{2} \times1.602= 4\times r$

$1.414\times 1.602=4r\\\frac{2.265}{4} =r\\r= 0.566 pm$

So, the radius of crystal in FCC will be 0.566 pm