Question

c) The equation
$x^{2} + ax + b = 0$
has two real roots
$\alpha \: and \: \beta$
. Show that
$xk + 1 = - (axk + b) \div xk$
is convergent near
$x = \alpha \: \: if | \alpha | > | \beta |$
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Answer 1

Answer:

$\huge\mathbb\blue{ANSWER}$

c) The equation

$x^{2} + ax + b = 0$

has two real roots

$\alpha \: and \: \beta$

. Show that

$xk + 1 = - (axk + b) \div xk$

is convergent near

$x = \alpha \: \: if | \alpha | > | \beta |$

.