Question

C
The height of an equilateraf a measure
9J3 Find its area.​

Answer 1

$\huge \bigstar ★ \huge\bold{\mathtt{\purple{A{\pink{N{\green{S{\blue{W{\red{E{\orange{R}}}}}}}}}}}}}★★$

We know that

Height of an equilateral triangle = √3/2 a

It is given that height = 9cm

So we get

√3/2 a = 9

On further calculation a = (9 × 2)/ √3

Multiplying both numerator and denominator by √3

We get

a = (9 × 2 × √3) / (√3 × √3)

So we get

Base = a = 6√3cm

We know that the area of an equilateral triangle = ½ × b × h

By substituting the values

Area of the equilateral triangle = ½ × 6√3 × 9

On further calculation

Area of the equilateral triangle = 27√3 cm2

By substituting the value of √3

Area of the equilateral triangle = 27 × 1.732 = 46.764

By correcting to 2 places of decimal

Area of the equilateral triangle = 46.76 cm2

Therefore, the area of an equilateral triangle = 46.76 cm2.

${{\red{\underline{Please \: \: Mark \: \: as \: \: \: Brainliest}}}}$