Question

c)
The length and breadth of a rectangle are 132 cm and 62 cm. find its perimeter at cost of fencing at the rate of 60 per meter
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Answer 1

CORRECTED QUESTION

The length and breadth of a rectangle are 132 cm and 62 cm. find its perimeter and cost of fencing at the rate of ₹ 60 per meter .

Answer:

$\red\bigstar$ Cost of fencing at the rate of ₹60/m = ₹ 232.80.

SOLUTION

Length of the rectangle = 132cm.

Breadth of the rectangle = 62cm.

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Perimeter of a rectangle = 2( l + b) , Where l is the length and b is the breadth of the rectangle.

Here,

l = 132 cm

b = 62 cm

⇒ Perimeter of the rectangle = 2(132 + 62)

⇒ Perimeter of the rectangle = 2 × 194

⇒ Perimeter of the rectangle = 388 cm.

Cost of fencing = Perimeter of the rectangle  × Rate of fencing

Here,

Perimeter of the rectangle = 388 cm = 3.88 m

Rate of fencing = ₹60/m

⇒ Cost of fencing = 3.88 × 60

⇒ Cost of fencing = ₹ 232.80

Answer 2

Answer:

length(l) of rectangle=132cm

breadth(b) of rectangle=62cm

perimeter of rectangle=2(l+b)

=2(132cm+62cm)

=2×194cm

=388cm

convert cm into m

1m=100cm

1cm=1/100m

388cm=388/100m

388cm=3.88m

cost of fencing 1m rectangle=Rs.60

cost of fencing 3.88m rectangle=3.88×60

=Rs.232.8

Step-by-step explanation:

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