Question

C)
The length of a rectangular field 8 meters more than its breadth. If perimeter of its
is 108m. Find the dimensions ? (AS-IV)​

Answer 1

Step-by-step explanation:

Let breadth be x and length be x+8.

Then 2(x+x+8)=108

4x+16=108

4x=92

x=92/4

x=23 m

Answer 2

Answer:

Let the breadth of the field be x metre...(1)

.°. length = 2(breadth)

.°. length = 2x metre...(2)

Step-by-step explanation:

Perimeter of rectangle = 2(l+b)

.°.108 = 2(x + 2x)

$.°. \: \frac{108}{2 \:} = 3x$

.°.54 = 3x

$.°. \frac{54}{3} = x$

.°. x = 18

Substituing x = 18 in (1),

breadth = 18 metre.

.°. length = 2(18)

.°. length = 36m.

Thus the field have dimesions, length = 36m. and breadth = 18m.