c) The lengths of the parallel sides of a trapezium are in the ratio 3:2 and the
distance between them is 10cm. If the area of the trapezium is 325 cm2, find
the length of the parallel sides.
harish123401pdnrjw:
i know the answer
Answers
Answered by
8
HERE'S YOUR ANSWER.....✌️✌️
1/2×(sum of parallel sides)× h = area of trapezium
let the no. of the ratio be 3x and 2x,
1/2×(2x+3x)×10= 325
=>x=13
the first side,
=2x
=2×13
=26
the other side,
= 3x
=3×13
=39
1/2×(sum of parallel sides)× h = area of trapezium
let the no. of the ratio be 3x and 2x,
1/2×(2x+3x)×10= 325
=>x=13
the first side,
=2x
=2×13
=26
the other side,
= 3x
=3×13
=39
Answered by
4
Let the parallel sides be 3x and 2x.
We know that area of trapezium= 1/2 × height × sum of parallel sides
Now putting given values
325 = 1/2 ×10 × (3x + 2x)
325 = 5× 5x
325 ÷ 25 = x
13 = x
The length of sides are;-
3x =75cm
2x = 50cm
We know that area of trapezium= 1/2 × height × sum of parallel sides
Now putting given values
325 = 1/2 ×10 × (3x + 2x)
325 = 5× 5x
325 ÷ 25 = x
13 = x
The length of sides are;-
3x =75cm
2x = 50cm
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