Question

c) The locus of a point which is at a distance of 3 units from (3, 2) is​

Answer 1

Answer:

x

2

+y

2

+4x−6y−12=0

Let an arbitrary point be P(x,y)

Then the distance of the point P from the point A(−2,3) is

d=

(x+2)

2

+(y−3)

2

d

2

=(x+2)

2

+(y−3)

2

Now the distance is given to be 5,

Hence

(x+2)

2

+(y−3)

2

=25

x

2

+y

2

+4x−6y+4+9=25

x

2

+y

2

+4x−6y+13=25

x

2

+y

2

+4x−6y−12=0.

Step-by-step explanation:

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