Question

c) The perimeter of a triangle is 10a2 + 25a + 10. Two of its sides
are 3a2 + 5a + 1 and a2 + 10a – 6. Find its third side.
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Answer 1

Step-by-step explanation:

Perimeter of the triangle = Sum of all sides

• perimeter = 10a²+25a+10
• first side = 3a²+5a+1
• second side = a²+10a-6
• third side = X

10a²+25a+10 = (3a²+5a+1) + (a²+10a-6) + X

10a²+25a+10 = 4a²+ 15a -5 + X

X = 10a²+25a+10 - ( 4a²+15a-5)

X = 6a²+10a+5

Answer 2

Answer:

Perimeter of triangle =a+b+c

a=3a2+5a+1

b=a2+10a-6

c=?

perimeter=10a2+25a+10

10a2+25a+10=(3a2+5a+1)+(a2+10a-6)+c

10a2+25a+10=4a2+15a-5+c

10a2+25a+10-4a2-15a+5=c

c=6a2+10a+15

Step-by-step explanation: