Question

c) The perimeter of a triangle is (x2y + 10) units. One of the sides is of length (x2y-4)
units and another side is (3-2x2y) units. Find the length of the third side. ​

Answer 1

Write down the radius length of each of the following circles: ... Find the equation of the circle which has the line segment joining (3,-4) to (-3, 4) as diameter. .... Make sure every term is on the left-hand side and the coefficients of r2 and y2 are equal to .....

x-y- 1 = 0;

x2 + y2 – 2x – 2y + 1 = 0

6. x-2y- 1 = 0;

x2 + y2 + 2x -8y-8=0).

Answer 2

The length of the third side is $2x^2y+11 \text{ units}$

Step-by-step explanation:

The perimeter of triangle is $x^2y+10$

Two Sides length are

$x^2y-4,3-2x^2y$

The perimeter of a triangle is the sum of all the three sides.

So, we have

$x^2y-4+3-2x^2y+\text{ third side }=x^2y+10$

Solve the equation to find the third side.

$-x^2y-1+\text{ third side }=x^2y+10\\\\\text{ third side }=x^2y+10+x^2y+1\\\\\text{ third side }=2x^2y+11$

Therefore, the length of the third side is $2x^2y+11$

#Learn More:

The perimeter of an equilateral triangle is 36 cm,then find the area of the triangle.

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