Question

c) The perimeter of a triangular field is 240 cm. If two of its sides are 78 cm and
50 cm, then find the area of triangular field.
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Answer 1

Step-by-step explanation:

P = 240

S = 240/2 = 120

By Heron's Formula

$area \: = \sqrt{s(s - a)(s - b)(s - c)}$

$area = \sqrt{120 \times 8 \times 70 \times 42}$

$area \: = 1680$

Area of the triangle = 1/2 *B*H

= 2 × 1680 = 50 × H

= 3360 = 50 × H

H = 3360/50

Height = 67.2 dm

The answer is 67.2 dm

Answer 2

Answer:

Step-by-step explanation:

P = 240

S = 240/2 = 120

By Heron's Formula

area \: = \sqrt{s(s - a)(s - b)(s - c)}area=

s(s−a)(s−b)(s−c)

area = \sqrt{120 \times 8 \times 70 \times 42}area=

120×8×70×42

area \: = 1680area=1680

Area of the triangle = 1/2 *B*H

= 2 × 1680 = 50 × H

= 3360 = 50 × H

H = 3360/50

Height = 67.2 dm

The answer is 67.2 dm