C)
The sum of three number in A.P. is -3, and
their product is 8. Then sum of squares of the
number is
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Step-by-step explanation:
AP : a - d, a, a + d
where, a = First term,
d = common difference
According to the Question,
a - d + a + a + d = -3
and
( a - d)(a)( a + d ) = 8
Solving the equations,
3a = -3
a = -1
And substitute the value of a in eq.2
( a - d)(a)( a + d ) = 8
( -1 - d)(-1)( -1 + d ) = 8
-((-1)^2 - (d)^2) = 8
-1+d^2 = 8
d^2 = 9
therefore, d = 3
So,The AP is a-d, a, a+d = -1 -3 , -1 , -1 +3
= -4,-1,2
sum of squares of the number = 16 + 1 + 4
= 21
ANSWER = 21
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