Question

c. The vertical distance is 75.0 m Since the top of the cliff or the point of
origin of the thrown object is zero, then the distance going downward must
be negative. Substituting the values, the equation will be.
-75.0 m= (-9.8 m/s) (1)
1.-75.0 m (2)
-9.8 m/s
5318
15.31 s2
d. Horizontal distance
dy = Vxt
= (3.5 m/s) (3.91 s)
(5)​

Answer 1

Answer:

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Step-by-step explanation:

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