C) Two men and 7 boys can clean an office in 14 days .3 men and 8 boys can do the
same in 11 days. In how many days will 8 men and 6 boys clean the office which
is 3 times bigger?
Answers
Step-by-step explanation:
This question can be solved in two steps:
Equate the work done by both groups in one day to find out the relation between work done by man and boy.
Once we have the relation from step 1 , use that to convert everything into one group to make the comparison easy.
2 men and 7 boys are required to complete the work in 14 days. So 28 men (2×14) and 98 boys (7×14) are required to complete the work in one day. 3 men and 8 boys are required to complete the work in 11 days. So 33 men (3×11) and 88 boys (8×11) are required to complete the work in one day. Now, equate the two cases as 28m+98b=33m+88b⟹1m=2b⟹1men=2boys . So now we can convert both the groups into one group (group of men or group of boys)
Converting both the groups as group of only men:
3 men and 8 boys= 3 men and 4 men = 7 men . So 7 men can finish the work in 11 days⟹ 11 men can finish the work in 7 days.
8 men and 6 boys= 8 men and 3 men = 11 men . So 11 men can finish the work in 7 days.
To complete the work of 3 times the actual work, 7×3=21days are required