Question

(c) Two numbers are in the ratio 53 if each increased by 10, the ratio between the new numbers so formed is 7:5, find the values of original numbers ​

Answer 1

Step-by-step explanation:

15 and 25

is the answer

Thanks.

Answer 2

Answer :

The original numbers are 20 & 12

Explanation :

Question says that,

Ratio of two numbers → 5 : 3

If 10 added to each the ratio becomes

→ 7 : 5

Let's suppose the original numbers are : $5x \:{\sf{and}} \:3x$

Now,

10 added to each

So,

the numbers are :

$(5x + 10) \: {\sf{and}}\: (3x + 10)$

According to the question :

${\implies (5x + 10) : (3x + 10) = 7 : 5}$

Solving for $\boldsymbol x$ :

$\implies \dfrac{(5x + 10)}{(3x + 10)} = \dfrac{7}{5}$

$\implies 5(5x + 10) = 7(3x + 10)$

$\implies 25x + 50 = 21x + 70$

$\implies 25x + 21x = 70 - 50$

$\implies 4x = 20$

$\implies x = \dfrac{20}{4}$

$\implies x = 5$

${ \therefore{ \sf{The \: value \: of {\boldsymbol{ x}} \: is \: 4}}}$

Hence, the numbers are :

• $5x = \bf 5(4) = 20$
• $3x = \bf 3(4) = 12$