Question

c. Two ropes 16 mand 20mlong are to be cut into small pieces of
equallengths. What will
be the maximum length oibach of the
pieces?​

Answer 1

Answer:

Step-by-step explanation:

Maximum length of the piece that has to be cut=H.C.F of 16m and 20m

Now HCF of 16 and 20 is 4

∴ Required length=4m