Question

(c) What volume of oxygen would react with 16 g of magnesium
in the reaction below?
2 Mg (s) + 0), (g) → 2MgO (s)​

Answer 1

Answer:

2 is the answer of this question

Answer 2

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Mg:O

2:1

16g:X g

X g=mass of oxygen=16/2=8g

no of moles=mass/molar mass

molar mass :16×2=32g/mol

let no of mole of oxygen be n

n=8/32

n=0.25moles

no of moles=volume/molar volume

molar volume=molar mass

n=volume/molar volume

0.25=v/32

v of oxygen=8cm³