(c) Write down the least integer value of : for which z>-4.
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OA: A
(0.000125)(0.0025)(0.00000125)∗10z=125∗10−6∗25∗10−4∗125∗10−8∗10z(0.000125)(0.0025)(0.00000125)∗10z=125∗10−6∗25∗10−4∗125∗10−8∗10z
=125∗25∗125∗10−6−4−8+z=125∗25∗125∗10−6−4−8+z
=125∗25∗125∗10−18+z=125∗25∗125∗10−18+z
125∗25∗125125∗25∗125 will end with 55 as unit's digit, there will be no 00 at unit's place.So for zz to be minimum,−18+z−18+z should be equal to 00.
−18+z=0−18+z=0
z=18
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