Question

(c X 3. Factorise (a) 6c2 - 4cd (d) pʻq - pq? +p?o? p (b) x2 – 3x² – 3x - (e) a (x + y) + b (x + y) 2 2 22​

Answer 1

Step-by-step explanation:

(c X 3. Factorise (a) 6c2 - 4cd (d) pʻq - pq? +p?o? p (b) x2 – 3x² – 3x - (e) a (x + y) + b (x + y) 2 2 22

Answer 2

Step-by-step explanation:

Suppose (a + b) and (c – d) are two binomials. By using the distributive law of multiplication over addition twice, we may find their product as given below.

(a + b) × (c – d) = a × (c – d) + b × (c – d)

= (a × c – a × d) + (b × c – b × d)

= ac – ad + bc – bd Let, a= 3p2,

b= q2, c= 2p2, d= 3q2

Now,

= 3p2× (2p2 – 3q2) + q2 × (2p2 – 3q2)

= [(3p2× 2p2) + (3p2× -3q2)] + [(q2 × 2p2) + (q2 × -3q2)] =

[6p4 – 9p2q2 + 2q2p2 – 3q4)]

= [6p4 – 7p2q2 – 3q4]