Question

(C) x-a is a factor of x3 – a²x + x + 2​

Answer 1

Answer:

here,

x-a=0

x=a

and,

p(x) = x^3-ax^2+x+2

substituting x=a in p(x) we get,

a^3-a*a^2+a+2=0

a^3-a^3+a+2=0

a+2=0

a=-2

Step-by-step explanation:

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Answer 2

since, x-a is a factor of p(x) =x³-a²x+x+2

then x-a=0

x=a

therefore ,p(a) =a³-a²a+a+2=0

=a³-a³+a+2=0

=a+2 =0

=a=-2