C = {x : x is perfect cube, 27 < x < 216}
Answers
Answer:
C = { 64 , 125 }
Step-by-step explanation:
Given: Set C = { x : x is perfect cube and 27 < x < 216 }
To find: Elements of set c and write in roaster form.
Element of Set C are perfect cube between 27 and 216.
A perfect cube is the result of multiplying a number three times by itself.
Here, 27 is perfect cube with cube root = 3 and 216 is also perfect cube with cube root = 6.
So, we have only number 4 and 5 between 3 & 6.
So, Set C contain Cubes of 4 and 5 that is 64 and 125.
Therefore, C = { 64 , 125 }
Answer:
C = { 64 , 125 }
Step-by-step explanation:
We given a set builder form of Set C.
We need to find roaster form of set or elements of set C.
Element of Set C are perfect cube between 27 and 216.
Perfect cube is a number whose cube root is a integer or we can say it is a number which obtained by multiplying an integers 3 times.
Here, 27 is perfect cube with cube root = 3 and 216 is also perfect cube with cube root = 6.
So, we have only number 4 and 5 between 3 & 6.
So, Set C contain Cubes of 4 and 5 that is 64 and 125.