Question

©
y +1 Y-1_1+ 2y
6 (1)
3
2.
3​

Answer 1

Answer:

(y+1)/3 - (y-1)/2=(1+2y)/3[2(y+ 1)-3(y-1)]/6=(1+2y)/3(2y+2-3y+3)/2=1+2y5-y=2 +4y3=5yy=3/5.