c0+2c1+4c2+...........+cn.2n=243 then n=
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Answer:
ANSWER
Fact: (1+x)
n
=
n
C
0
+
n
C
1
x+
n
C
2
x
2
+
n
C
3
x
3
+............+
n
C
n
x
n
Substitute x=2 in above identity
(1+2)
n
=
n
C
0
+
n
C
1
(2)+
n
C
2
(2)
2
+
n
C
3
(2)
3
+............+
n
C
n
(2)
n
∴
n
C
0
+2⋅
n
C
1
+4⋅
n
C
2
+8⋅
n
C
3
+........+2
n
⋅
n
C
n
=3
n
Step-by-step explanation:
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