Question

C0 + 2Cl20 __ C+4Cl-1 Analyse the above equation and list a)Oxidised atom b)Equation of oxidation c) Reduced atom d)Reducing agent.
help me please​

Answer 1

Answer:

it is a reducing agent.. chloride is oxidised hence it act as reducing agent

Answer 2

Answer:

Chemical equation: $C^0 (s) + 2Cl_2^0 (g) -> C^{IV}Cl_4^{-I} (l)$

Explanation:

Now, you can configure that:

a) $C^0$ is the oxidised atom which has been oxidised to $C^{IV}$

b) Equation of oxidation can be written as:

$C^0 - 4e^- ->C^{IV}$       (Oxidation)

c) As $C^0$ is the oxidised atom, therefore $Cl_2^0$ is the reduced atom.

d) The one which gets oxidised is the reducing agent.

Therefore, C is the reducing agent.

Hope you got that.

Thank you.