Question

C12H22O11 oxidation state of c​

Answer 1

$\maltese$Given to find the oxidation state of the compound :-

$C_{12}H_{22} O_{11}$

$\maltese$SOLUTION :-

As we know that,

Oxidation number of Hydrogen is +1 Oxidation number of Oxygen is -2

So,

Let the oxidation number of Carbon is x

There are 12 atoms of Carbon = 12x There are 22 atoms of Hydrogen= 22(1)

There are 11 atoms of Oxygen = 11(-2) Also we know that ,

Sum of oxidation state of the compound should be 0

So, 12x + 22(1) + 11(-2) = 0

12x +22-22 =0

12x +0 =0

12x =0

x = 0

So, the oxidation state of the Carbon in the compound $C_{12}H_{22} O_{11}$ is 0

$\maltese$Know more :-

There are some elements to know their oxidation state:-

• Oxidation number of 1A group elements is +1
• Oxidation number of 2ndA group elements are + 2

Some of the group elements exhibits different oxidation states like D-block elements

Oxidation of a number can be positive , negative , 0 , fractional etc