c² - 20d-d Solve this question using the formula of ( a²+2ab+ b²) (a²-2ab-b²)
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What is the formula for (a-b-c)²?
We know the algebraic identity,
( x + y + z )²
= x² + y² + z² + 2xy + 2yz + 2zx
Now ,
( a - b - c )²
=[ a² + ( - b )² + ( -c )² ]²
=a²+(-b)²+(-c)²+2a(-b)+2(-b)(-c)+2(-c)a
= a² + b² + c² - 2ab + 2bc - 2ca
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