C2 h5 cl on heating with alcoholic koh will produce
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C2h5cl on heating with alcoholic Koh will produce C2H4
Chemical Process:
alc. KOH is used for dehydrohalogenation in this chemical reaction.
The reaction is carried out as follows:
C2h5cl + alc.KOH → CH2=Ch2 + KCL + H2O
Ethene is formed in this reaction along with potassium chloride and water.
Formation of Ethanol:
We can convert CH2=CH2 into Ethanol in the presence of aqueous H2SO4
The reaction is carried out as follows:
CH2=CH2 + H20 → C2H5OH
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Learn More about the formation of ethene.
Explain the formation of the ethene molecule with a diagram
https://brainly.in/question/30468479?msp_srt_exp=5
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Answer:
Ethene and Hydrochloric acid.
Explanation:
C₂H₅Cl -----⁽alc KOH⁾-------------> C₂H₄ + HCl
- In this reaction chloroethane reacts with alcoholic potassium hydroxide to form ethene carrying a double bond and hydrochloric acid.
- The alcoholic KOH acts as the base which will attack the hydrogen atom to form water.
- After removal of hydrogen the bond will shift to form ethene and remove the chlorine.
- The chlorine acts as a nucleophile which will attack the positive potassium ion to form potassium chloride.
- This reaction is an example of elimination reaction.
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