c2h2+2h2=c2h6
if the rate of appearance of c2h6 is 0.6 moles/dm³.sec what is rate of disappearance of h2 ?
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Answer:
Let 1 mole of ethane is passed over a suitable catalyst.
Let x moles of ethane dissociate to reach the equilibrium.
The equilibrium number of moles of ethane, ethylene and hydrogen are 1-x, x and x moles respectively
Explanation:
K
p
=
P
ethane
P
ethylene
P
hydrogen
1−x
x
2
=5×10
−2
x
2
+0.05x−0.05=0
x=
2
−0.05+
(0.05)
2
+4×0.05
=0.20atm
The partial pressure of ethane is the product of mole fraction and total pressure.
0.80=mole fraction×1.2
Mole percentage of ethane =
1.2
0.8
×100=66.66
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