Chemistry, asked by HDeka, 10 months ago

C2H3O2 Vapor density 59 what is the molecule formula

Answers

Answered by starock20kamalrock

0

Answer:

C4H6O4

Explanation:

weight of C2H3O2 = 59

weight of actual comp = 2 X vapour dens

= 2 X 59 = 118

n = weight actual/empirical

= 118/59 = 2

=> formula is (C2H3O2)n = (C2H3O2)2

that is C4H6O4

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