Question

C2H4 + 3O2 → 2CO2 + 2H2O ΔH = ‒1411 kJ mol‒1
2C2H6 + 7O2 → 4CO2 + 6H2O ΔH = ‒3120 kJ mol‒1
2H2 + O2 → 2H2O ΔH = ‒572 kJ mol‒1
Calculate the enthalpy for the hydrogenation of ethene to ethane:
C2H4 + H2 → C2H6

Answer 1

Answer:

C2H4+302=2C02+2H20 TRIANGLE H=1411kj mol-1

2C2H6+702=4CO2+6H20 TRIANGLE H =-3120KJ MOL-1

2H2+o2=2H20 triangle h =-572kj mol 1

C2H4=H2=C2H6

Explanation:

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