C2H5
(CHCOOH)n + AgNO3 (Excess) —
Silver salt
Ag (metal)
CzHs
If 0.5 mole of silver salt is taken and weight of residuc obtained is 216 g (Ag = 108 gmol). Then which of the
following is are correct:
n=4
n = 2
Option 1
Option 2
M. wt. of silver
salt is 718 g/mol
M. wt. of silver
salt is 388 g/mol
Answers
Answered by
2
Explanation:
mass of 0.5 mole of silver =
No . of moles = Given mass / molar mass
mass = no. of moles × molar mass
= 0.5 × 108
= 54g
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