Question

C2h5oh +3o2 gives 2co2+3 h2o if delta u is =-1373kj/mol at 298k calculate delta h

Answer 1

delta H = delta U + delta nRT

Given:

delta n= 5-3 =2

temp.= 298 k

delta U = -1373 kj/mol

delta H= delta U + delta nRT

= -1373 + 2×8.314×298

= -1373 + 4955.144

= 3582.144 joule

Value of delta H is 3582.144 joule