Question

C2H6 +02→CO2+H2O,What is the value of delta H in this reaction​

Answer 1

First we need to write out the chemical reaction in a balanced form

2C2H6+7O2⟶4CO2+6H2O2C2H6+7O2⟶4CO2+6H2O

Then we can calculate the enthalpy of combustion (i.e. reaction with oxygen) as

ΔcH∘=ΣΔHf−ΣΔHiΔcH∘=ΣΔHf−ΣΔHi

where ΣΔHfΣΔHf is the enthalpy of products (final) and ΣΔHiΣΔHi is the enthalpy of reactants (initial). Their values are the following:

ΔH(C2H6)=−84kJ/molΔH(C2H6)=−84kJ/mol

ΔH(CO2)=−394kJ/molΔH(CO2)=−394kJ/mol

ΔH(H2O)=−286kJ/molΔH(H2O)=−286kJ/mol

Thus, by taking into account the coefficients of the chemical reaction equation, we can calculate

ΔcH∘=((4⋅(−394)+6⋅(−286))−(2⋅(−84)))/2kJ/molΔcH∘=((4⋅(−394)+6⋅(−286))−(2⋅(−84)))/2kJ/mol

=−1562kJ/mol

❤Sweetheart❤

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