C3H4(prop-1-yne)+(I)B2H6(ii)H2O(III)CH3COOH->?
PLEASE GIVE THE MECHANISM OF THE REACTION.....
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It is Propyne.
The formula for alkyne group is CnH2n-2 [ Where n is the no. of atoms] . So for Propyne three carbon atoms and four hydrogen atoms so
C3H2*3-2 =4 = C3H4
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